Let's solve the problem step by step.
We need to subtract \( \frac{1}{2}(z + 4) - 3\left(\frac{1}{4}z + 1\right) \).
Step 1: Distribute \( \frac{1}{2} \) to \( (z + 4) \)
When we multiply, we do: \[ \frac{1}{2} \times z + \frac{1}{2} \times 4 = \frac{1}{2}z + 2 \] So, \( \frac{1}{2}(z + 4) = \frac{1}{2}z + 2 \).
Step 2: Distribute \( -3 \) to \( \left( \frac{1}{4} z + 1 \right) \)
First, multiply: \[ -3 \times \frac{1}{4}z + (-3) \times 1 = -\frac{3}{4}z - 3 \] So, \( -3\left(\frac{1}{4}z + 1\right) = -\frac{3}{4}z - 3 \).
Step 3: Write the whole expression together
Now, we look at the original problem again: \[ \frac{1}{2}z + 2 - \left(\frac{3}{4}z + 3\right) \] This becomes: \[ \frac{1}{2}z + 2 - \frac{3}{4}z - 3 \]
Step 4: Combine like terms
First, let's combine the \( z \) terms. We have: \[ \frac{1}{2}z - \frac{3}{4}z \] To do this, we need to have a common denominator. The common denominator for 2 and 4 is 4.
So we change \( \frac{1}{2}z \) to \( \frac{2}{4}z \): \[ \frac{2}{4}z - \frac{3}{4}z = -\frac{1}{4}z \]
Now we combine the constant terms: \[ 2 - 3 = -1 \]
Step 5: Put it all together
So our final answer is: \[ -\frac{1}{4}z - 1 \]
In short, we found that when you subtract \( \frac{1}{2}(z + 4) \) and \( 3\left(\frac{1}{4}z + 1\right) \), you get: \[ -\frac{1}{4}z - 1 \]