Question
A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 meters per second. By the time it reached the buoy, it was going 10 meters per second.
What was the average velocity of the boat?
Responses
−3.33 m/s2
negative 3.33 meters per second squared
−1.11 m/s
negative 1.11 meters per second
+1.11 m/s
plus 1.11 meters per second
+3.33 m/s
plus 3.33 meters per second
What was the average velocity of the boat?
Responses
−3.33 m/s2
negative 3.33 meters per second squared
−1.11 m/s
negative 1.11 meters per second
+1.11 m/s
plus 1.11 meters per second
+3.33 m/s
plus 3.33 meters per second
Answers
GPT-4o mini
To calculate the average velocity of the speedboat, we need to use the formula for average velocity:
\[
\text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}}
\]
In this case, the boat travels a total distance (which is also the displacement, since it moves in a straight line) of 20 meters in a time of 18 seconds.
\[
\text{Average Velocity} = \frac{20 \, \text{m}}{18 \, \text{s}} \approx 1.11 \, \text{m/s}
\]
The average velocity is approximately +1.11 m/s (it's positive because the boat moved away from the dock in a defined positive direction).
So, the correct response is **+1.11 m/s** (plus 1.11 meters per second).
\[
\text{Average Velocity} = \frac{\text{Total Displacement}}{\text{Total Time}}
\]
In this case, the boat travels a total distance (which is also the displacement, since it moves in a straight line) of 20 meters in a time of 18 seconds.
\[
\text{Average Velocity} = \frac{20 \, \text{m}}{18 \, \text{s}} \approx 1.11 \, \text{m/s}
\]
The average velocity is approximately +1.11 m/s (it's positive because the boat moved away from the dock in a defined positive direction).
So, the correct response is **+1.11 m/s** (plus 1.11 meters per second).