2HI(g)--> H2(g) + I2(g)
The rate law for the decomposition of HI is r=k[HI]^2. The rate of the rxn was found experimentally to b 2.5 x 10^4 mol/L x s where the HI concentration was 0.0558 M.
Are these values ready to plug in to the equation, or because there is 2HI, do I have to divide the moles by 2?
1 answer
I think the rate quoted is good as is; if any division/multiplication/etc are needed, they should have been done when quoting the rate.
0 answers