Question
A glass marble has a diameter of 17 millimeters. What is the approximate volume of the marble? Use 3.14 for .
A.
2,571.14 cubic millimeters
B.
302.49 cubic millimeters
C.
20,569.09 cubic millimeters
D.
1,209.95 cubic millimeters
A.
2,571.14 cubic millimeters
B.
302.49 cubic millimeters
C.
20,569.09 cubic millimeters
D.
1,209.95 cubic millimeters
Answers
Answered by
GPT-4o mini
To find the volume of a glass marble, which is shaped like a sphere, we can use the formula for the volume of a sphere:
\[
V = \frac{4}{3} \pi r^3
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the sphere.
Given the diameter of the marble is 17 millimeters, we can find the radius by dividing the diameter by 2:
\[
r = \frac{17}{2} = 8.5 \text{ millimeters}
\]
Now we can substitute the value of \( r \) into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times (8.5)^3
\]
Calculating \( (8.5)^3 \):
\[
(8.5)^3 = 614.125
\]
Now we substitute this back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 614.125
\]
Calculating:
\[
V \approx \frac{4}{3} \times 3.14 \times 614.125 \approx \frac{4 \times 3.14 \times 614.125}{3}
\]
First, calculate \( 4 \times 3.14 = 12.56 \).
Now calculate \( 12.56 \times 614.125 \):
\[
12.56 \times 614.125 \approx 7719.07875
\]
Now, divide by 3:
\[
\frac{7719.07875}{3} \approx 2573.02625
\]
Taking this volume into account, it is approximately \( 2573.03 \text{ cubic millimeters} \).
Now, rounding this value, we find that it is closest to option A:
\[
\text{A. } 2,571.14 \text{ cubic millimeters}
\]
Thus, the correct choice is:
**A. 2,571.14 cubic millimeters**.
\[
V = \frac{4}{3} \pi r^3
\]
Where:
- \( V \) is the volume,
- \( \pi \) is approximately 3.14,
- \( r \) is the radius of the sphere.
Given the diameter of the marble is 17 millimeters, we can find the radius by dividing the diameter by 2:
\[
r = \frac{17}{2} = 8.5 \text{ millimeters}
\]
Now we can substitute the value of \( r \) into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times (8.5)^3
\]
Calculating \( (8.5)^3 \):
\[
(8.5)^3 = 614.125
\]
Now we substitute this back into the volume formula:
\[
V = \frac{4}{3} \times 3.14 \times 614.125
\]
Calculating:
\[
V \approx \frac{4}{3} \times 3.14 \times 614.125 \approx \frac{4 \times 3.14 \times 614.125}{3}
\]
First, calculate \( 4 \times 3.14 = 12.56 \).
Now calculate \( 12.56 \times 614.125 \):
\[
12.56 \times 614.125 \approx 7719.07875
\]
Now, divide by 3:
\[
\frac{7719.07875}{3} \approx 2573.02625
\]
Taking this volume into account, it is approximately \( 2573.03 \text{ cubic millimeters} \).
Now, rounding this value, we find that it is closest to option A:
\[
\text{A. } 2,571.14 \text{ cubic millimeters}
\]
Thus, the correct choice is:
**A. 2,571.14 cubic millimeters**.
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