Asked by Mickey
1.The base of a triangle is 5cm greater than the height. The area is 33cm(2). Find the height and the length of the base?
Height?
Base?
2. Factor
X(2)-7x
3.Factor
5a(6)-1080a(3)
4. Find the GCF
5x(9),5x,-20=
For this one I think the gcf is 5 Is this correct?
5. Factor by grouping
8x(3)-*x(2)-x+1=
Height?
Base?
2. Factor
X(2)-7x
3.Factor
5a(6)-1080a(3)
4. Find the GCF
5x(9),5x,-20=
For this one I think the gcf is 5 Is this correct?
5. Factor by grouping
8x(3)-*x(2)-x+1=
Answers
Answered by
Reiny
1. height -- x
base -- x+5
solve (1/2)x(x+5) = 33
(you will end up with a quadratic which factors very easily)
2. Do you mean x^2 - 7x ??
then x(x-7)
3. do you mean 5a^6 - 1080a^3 ??
I see a common factor of 5a^3
4. yes
5. retype the question, don't know what the -* is supposed to mean. Also use 8x^3 for "8 x cubed"
base -- x+5
solve (1/2)x(x+5) = 33
(you will end up with a quadratic which factors very easily)
2. Do you mean x^2 - 7x ??
then x(x-7)
3. do you mean 5a^6 - 1080a^3 ??
I see a common factor of 5a^3
4. yes
5. retype the question, don't know what the -* is supposed to mean. Also use 8x^3 for "8 x cubed"
Answered by
PsyDAG
1. B = H + 5
Area = 1/2 BH
Substitute H + 5 for B in the second equation and solve for H. Put that value in the first equation to find B. Check by putting both values into the second equation.
2. X^2 = X squared online
X^2 + 7X = X(X + 7)
I will let you do 3 using the same process.
4 is correct.
5. I'm not sure what this formula is.
8X^3 - X^2 - X + 1 (?)
Area = 1/2 BH
Substitute H + 5 for B in the second equation and solve for H. Put that value in the first equation to find B. Check by putting both values into the second equation.
2. X^2 = X squared online
X^2 + 7X = X(X + 7)
I will let you do 3 using the same process.
4 is correct.
5. I'm not sure what this formula is.
8X^3 - X^2 - X + 1 (?)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.