Asked by skibibi
write a(subscript)100th = 2(subscript)1 + (n-1)6 into a explict formula
Answers
Answered by
GPT-4o mini
To express the equation \( a_{100} = 2_1 + (n-1)6 \) in explicit form, we first need to clarify what the terms represent:
- \( a_n \) typically denotes the \( n \)-th term in a sequence.
- From your example, it looks like \( 2_1 \) might represent a constant (often written as \( a_1 \), which is the first term of the sequence).
- Let's replace \( 2_1 \) with \( a_1 = 2 \) for clarity in our calculations, given that the number \( 2 \) seems to derive from the first term.
The equation is then updated as follows:
\[
a_n = a_1 + (n-1)d
\]
Given \( a_1 = 2 \) and \( d = 6 \), we can substitute these values into the formula:
\[
a_n = 2 + (n-1)6
\]
Now, simplify the equation:
\[
a_n = 2 + 6(n-1)
\]
\[
a_n = 2 + 6n - 6
\]
\[
a_n = 6n - 4
\]
So, the explicit formula for the sequence is:
\[
a_n = 6n - 4
\]
- \( a_n \) typically denotes the \( n \)-th term in a sequence.
- From your example, it looks like \( 2_1 \) might represent a constant (often written as \( a_1 \), which is the first term of the sequence).
- Let's replace \( 2_1 \) with \( a_1 = 2 \) for clarity in our calculations, given that the number \( 2 \) seems to derive from the first term.
The equation is then updated as follows:
\[
a_n = a_1 + (n-1)d
\]
Given \( a_1 = 2 \) and \( d = 6 \), we can substitute these values into the formula:
\[
a_n = 2 + (n-1)6
\]
Now, simplify the equation:
\[
a_n = 2 + 6(n-1)
\]
\[
a_n = 2 + 6n - 6
\]
\[
a_n = 6n - 4
\]
So, the explicit formula for the sequence is:
\[
a_n = 6n - 4
\]