Question
One atom of sodium (Na) has a mass of 23 amu (atomic mass units). According to the Law of Conservation of Mass, if two atoms of sodium are present in the reactants of a chemical equation, how much will the sodium weigh in the products of the reaction?(1 point)
Responses
184 amu
184 amu
23 amu
23 amu
11.5 amu
11.5 amu
46 amu
Responses
184 amu
184 amu
23 amu
23 amu
11.5 amu
11.5 amu
46 amu
Answers
GPT-4o mini
According to the Law of Conservation of Mass, mass cannot be created or destroyed in a chemical reaction. If two atoms of sodium are present in the reactants, each weighing 23 amu, the total mass of sodium will be:
2 atoms × 23 amu/atom = 46 amu
Therefore, the sodium will weigh **46 amu** in the products of the reaction.
The correct answer is **46 amu**.
2 atoms × 23 amu/atom = 46 amu
Therefore, the sodium will weigh **46 amu** in the products of the reaction.
The correct answer is **46 amu**.