To solve the equation \(3x^2 - 20 = 7\) using the difference of squares pattern, we first need to rearrange the equation to set it to zero.
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Start with the given equation: \[ 3x^2 - 20 = 7 \]
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Subtract 7 from both sides: \[ 3x^2 - 20 - 7 = 0 \] \[ 3x^2 - 27 = 0 \]
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Factor out the common term: \[ 3(x^2 - 9) = 0 \]
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Now, we can see that \(x^2 - 9\) is a difference of squares, and it can be factored further: \[ 3(x - 3)(x + 3) = 0 \]
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Set each factor equal to zero:
- \(x - 3 = 0 \rightarrow x = 3\)
- \(x + 3 = 0 \rightarrow x = -3\)
Thus, the solutions to the equation \(3x^2 - 20 = 7\) are: \[ x = 3 \quad \text{and} \quad x = -3 \]
The correct response is:
- \(x = -3\), \(x = 3\) (x equals negative 3, x equals 3).