To determine which of the provided equations has the solution set \( x = {-95, 3} \), we can analyze each equation one by one:
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For \( (x + 3)(9x - 5) = 0 \):
- Set \( x + 3 = 0 \) gives \( x = -3 \).
- Set \( 9x - 5 = 0 \) gives \( 9x = 5 \Rightarrow x = \frac{5}{9} \).
- Solutions: \( x = -3, \frac{5}{9} \) (Not our set).
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For \( (x - 3)(5x + 9) = 0 \):
- Set \( x - 3 = 0 \) gives \( x = 3 \).
- Set \( 5x + 9 = 0 \) gives \( 5x = -9 \Rightarrow x = -\frac{9}{5} \).
- Solutions: \( x = 3, -\frac{9}{5} \) (Not our set).
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For \( -3x(5x + 9) = 0 \):
- Set \( -3x = 0 \) gives \( x = 0 \).
- Set \( 5x + 9 = 0 \) gives \( 5x = -9 \Rightarrow x = -\frac{9}{5} \).
- Solutions: \( x = 0, -\frac{9}{5} \) (Not our set).
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For \( (x - 3)(9x + 5) = 0 \):
- Set \( x - 3 = 0 \) gives \( x = 3 \).
- Set \( 9x + 5 = 0 \) gives \( 9x = -5 \Rightarrow x = -\frac{5}{9} \).
- Solutions: \( x = 3, -\frac{5}{9} \) (Not our set).
Since none of the provided options yield the solutions \( -95 \) or \( 3 \), there must be an error in provided equations. For the correct solution set, the equation should give \( x = -95 \) and \( x = 3 \).
The factorization that provides these roots should look like: \[ (x - 3)(x + 95) = 0 \] Hence, if this option was present, it would be the correct one.
Final Answer: None of the provided equations have the solution set \( x = {-95, 3} \).