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Which equation matches the solution set of {5} ?(1 point) Responses 3x5+4=7 Start Fraction 3 x over 5 End Fraction plus 4 equal...Asked by nut
Which equation matches the solution set of {5}?(1 point)
Responses
3x5+4=7
Start Fraction 3 x over 5 End Fraction plus 4 equals 7
x+x−9=1+x
x plus x minus 9 equals 1 plus x
2x−20=30
2 x minus 20 equals 30
x2−10=15
Responses
3x5+4=7
Start Fraction 3 x over 5 End Fraction plus 4 equals 7
x+x−9=1+x
x plus x minus 9 equals 1 plus x
2x−20=30
2 x minus 20 equals 30
x2−10=15
Answers
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Answered by
GPT-4o mini
To find the equation that matches the solution set of {5}, we need to solve each equation and see which one has 5 as its solution.
1. **3x/5 + 4 = 7**
\[
3x/5 + 4 = 7
\]
Subtract 4 from both sides:
\[
3x/5 = 3
\]
Multiply both sides by 5:
\[
3x = 15
\]
Divide both sides by 3:
\[
x = 5
\]
2. **x + x - 9 = 1 + x**
\[
2x - 9 = 1 + x
\]
Subtract x from both sides:
\[
x - 9 = 1
\]
Add 9 to both sides:
\[
x = 10
\]
3. **2x - 20 = 30**
\[
2x - 20 = 30
\]
Add 20 to both sides:
\[
2x = 50
\]
Divide both sides by 2:
\[
x = 25
\]
4. **x^2 - 10 = 15**
\[
x^2 - 10 = 15
\]
Add 10 to both sides:
\[
x^2 = 25
\]
Take the square root of both sides:
\[
x = 5 \quad \text{or} \quad x = -5
\]
From the calculations, the first equation \(3x/5 + 4 = 7\) has the solution \(x = 5\), and the fourth equation \(x^2 - 10 = 15\) also has \(x = 5\) (along with \(x = -5\)).
Therefore, the equations that match the solution set of {5} are:
- **3x/5 + 4 = 7**
- **x^2 - 10 = 15**
However, if we are looking for only one equation that matches specifically {5}, the best choice is:
- **3x/5 + 4 = 7**.
1. **3x/5 + 4 = 7**
\[
3x/5 + 4 = 7
\]
Subtract 4 from both sides:
\[
3x/5 = 3
\]
Multiply both sides by 5:
\[
3x = 15
\]
Divide both sides by 3:
\[
x = 5
\]
2. **x + x - 9 = 1 + x**
\[
2x - 9 = 1 + x
\]
Subtract x from both sides:
\[
x - 9 = 1
\]
Add 9 to both sides:
\[
x = 10
\]
3. **2x - 20 = 30**
\[
2x - 20 = 30
\]
Add 20 to both sides:
\[
2x = 50
\]
Divide both sides by 2:
\[
x = 25
\]
4. **x^2 - 10 = 15**
\[
x^2 - 10 = 15
\]
Add 10 to both sides:
\[
x^2 = 25
\]
Take the square root of both sides:
\[
x = 5 \quad \text{or} \quad x = -5
\]
From the calculations, the first equation \(3x/5 + 4 = 7\) has the solution \(x = 5\), and the fourth equation \(x^2 - 10 = 15\) also has \(x = 5\) (along with \(x = -5\)).
Therefore, the equations that match the solution set of {5} are:
- **3x/5 + 4 = 7**
- **x^2 - 10 = 15**
However, if we are looking for only one equation that matches specifically {5}, the best choice is:
- **3x/5 + 4 = 7**.
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