Asked by Someone__:)

What is the volume of the pyramid? h=11 w=7 l=10

Answers

Answered by Someone__:)
What is the volume of the pyramid in cubic feet? h=20 l=24 w=15
Answered by Someone__:)
A right rectangular pyramid has an altitude of 22.3 inches, a length of 6.75 inches, and a width of 10.25 inches. What is the volume of the pyramid in cubic inches?
Answered by Someone__:)
try again
Answered by GPT-4o mini
To find the volume of a pyramid, you can use the formula:

\[
\text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]

For a rectangular pyramid, the base area can be calculated as:

\[
\text{Base Area} = \text{width} \times \text{length} = w \times l
\]

In this case, you provided \( h = 11 \), \( w = 7 \), and \( l = 10 \).

First, calculate the base area:

\[
\text{Base Area} = 7 \times 10 = 70
\]

Now plug this into the volume formula:

\[
\text{Volume} = \frac{1}{3} \times 70 \times 11
\]
\[
\text{Volume} = \frac{1}{3} \times 770
\]
\[
\text{Volume} = \frac{770}{3} \approx 256.67
\]

So, the volume of the pyramid is approximately \( 256.67 \) cubic units.
Answered by GPT-4o mini
To find the volume of a pyramid, you can use the formula:

\[
\text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]

For a rectangular pyramid, the base area is given by:

\[
\text{Base Area} = w \times l
\]

Given \( h = 20 \) feet, \( w = 15 \) feet, and \( l = 24 \) feet, let's calculate the base area first:

\[
\text{Base Area} = 15 \times 24 = 360 \text{ square feet}
\]

Now, plug this into the volume formula:

\[
\text{Volume} = \frac{1}{3} \times 360 \times 20
\]
\[
\text{Volume} = \frac{7200}{3}
\]
\[
\text{Volume} = 2400 \text{ cubic feet}
\]

Thus, the volume of the pyramid is **2400 cubic feet**.
Answered by GPT-4o mini
To find the volume of a right rectangular pyramid, you can use the formula:

\[
\text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]

For a rectangular pyramid, the base area is given by:

\[
\text{Base Area} = \text{length} \times \text{width} = l \times w
\]

Given:
- Height (\( h \)) = 22.3 inches
- Length (\( l \)) = 6.75 inches
- Width (\( w \)) = 10.25 inches

First, calculate the base area:

\[
\text{Base Area} = 6.75 \times 10.25 = 69.1875 \text{ square inches}
\]

Now plug this into the volume formula:

\[
\text{Volume} = \frac{1}{3} \times 69.1875 \times 22.3
\]
\[
\text{Volume} = \frac{1}{3} \times 1547.1875 \approx 515.7292
\]

Thus, the volume of the pyramid is approximately **515.73 cubic inches**.
Answered by GPT-4o mini
Let's recalculate the volume of the right rectangular pyramid step by step, ensuring accuracy.

The formula for the volume \( V \) of a pyramid is:

\[
V = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]

### Given:
- Height (\( h \)) = 22.3 inches
- Length (\( l \)) = 6.75 inches
- Width (\( w \)) = 10.25 inches

### Step 1: Calculate the Base Area
The base area \( A \) of the pyramid is calculated as:

\[
\text{Base Area} = l \times w = 6.75 \times 10.25
\]

Calculating this:

\[
\text{Base Area} = 6.75 \times 10.25 = 69.1875 \text{ square inches}
\]

### Step 2: Calculate the Volume
Now, use the base area to calculate the volume:

\[
V = \frac{1}{3} \times \text{Base Area} \times h
\]
\[
V = \frac{1}{3} \times 69.1875 \times 22.3
\]

Now calculate the volume:

1. Calculate \( 69.1875 \times 22.3 \):

\[
69.1875 \times 22.3 = 1547.6875
\]

2. Now divide by 3:

\[
V = \frac{1547.6875}{3} \approx 515.8958333
\]

Thus, the volume of the pyramid is approximately **515.90 cubic inches** when rounded to two decimal places. Thank you for your patience, and I apologize for any confusion earlier.

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