To solve the factored quadratic equation \((19x−3)(9+x)=0\), we can set each factor equal to zero.
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First factor: \(19x - 3 = 0\) \[ 19x = 3 \implies x = \frac{3}{19} \]
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Second factor: \(9 + x = 0\) \[ x = -9 \]
Thus, the solutions to the equation are \(x = \frac{3}{19}\) and \(x = -9\).
The solution set is: \[ { -9, \frac{3}{19} } \]
Therefore, the correct response is: The solution set is \( x = { -9, \frac{3}{19} } \).