Question
Probability Unit Test
5 of 185 of 18 Items
Question
A standard deck of cards has 52 cards. The 52 cards are divided into four suits: diamonds, clubs, hearts, and spades. Diamonds and hearts are red cards, and clubs and spades are black cards. Suppose you choose a card from the deck. Let event A
be you choose a red card and event B
you choose an ace. Determine P(A and B)
, P(A)
, and P(B)
, and state whether events A
and B
are independent.
Enter the first three answers in fraction form. Reduce your answer.
(2 points)
P(A and B)=
;
P(A)=
;
P(B)=
;
Enter 1 if events A
and B
are dependent. Enter 2 if events A
and B
are independent
5 of 185 of 18 Items
Question
A standard deck of cards has 52 cards. The 52 cards are divided into four suits: diamonds, clubs, hearts, and spades. Diamonds and hearts are red cards, and clubs and spades are black cards. Suppose you choose a card from the deck. Let event A
be you choose a red card and event B
you choose an ace. Determine P(A and B)
, P(A)
, and P(B)
, and state whether events A
and B
are independent.
Enter the first three answers in fraction form. Reduce your answer.
(2 points)
P(A and B)=
;
P(A)=
;
P(B)=
;
Enter 1 if events A
and B
are dependent. Enter 2 if events A
and B
are independent
Answers
GPT-4o mini
To solve for the probabilities of events \(A\) and \(B\) and determine their independence, we will follow these steps:
1. **Identify the events:**
- Event \(A\) is choosing a red card (diamonds or hearts).
- Event \(B\) is choosing an ace.
2. **Calculate \(P(A)\):**
- There are 26 red cards in a standard deck (13 diamonds + 13 hearts).
- The total number of cards is 52.
\[
P(A) = \frac{26}{52} = \frac{1}{2}
\]
3. **Calculate \(P(B)\):**
- There are 4 aces in a standard deck (one for each suit).
\[
P(B) = \frac{4}{52} = \frac{1}{13}
\]
4. **Calculate \(P(A \text{ and } B)\):**
- For event \(A \text{ and } B\) (choosing a red card that is also an ace), the relevant aces are the Ace of Diamonds and the Ace of Hearts. There are 2 red aces.
\[
P(A \text{ and } B) = \frac{2}{52} = \frac{1}{26}
\]
5. **Determine independence:**
- To check if events \(A\) and \(B\) are independent, we need to see if:
\[
P(A \text{ and } B) = P(A) \times P(B)
\]
- Calculate \(P(A) \times P(B)\):
\[
P(A) \times P(B) = \frac{1}{2} \times \frac{1}{13} = \frac{1}{26}
\]
- Since \(P(A \text{ and } B) = P(A) \times P(B)\), events \(A\) and \(B\) are independent.
Putting it all together:
1. \(P(A \text{ and } B) = \frac{1}{26}\)
2. \(P(A) = \frac{1}{2}\)
3. \(P(B) = \frac{1}{13}\)
4. Events \(A\) and \(B\) are independent (enter 2).
Final answers:
- \(P(A \text{ and } B) = \frac{1}{26}\)
- \(P(A) = \frac{1}{2}\)
- \(P(B) = \frac{1}{13}\)
- Events are independent (2).
1. **Identify the events:**
- Event \(A\) is choosing a red card (diamonds or hearts).
- Event \(B\) is choosing an ace.
2. **Calculate \(P(A)\):**
- There are 26 red cards in a standard deck (13 diamonds + 13 hearts).
- The total number of cards is 52.
\[
P(A) = \frac{26}{52} = \frac{1}{2}
\]
3. **Calculate \(P(B)\):**
- There are 4 aces in a standard deck (one for each suit).
\[
P(B) = \frac{4}{52} = \frac{1}{13}
\]
4. **Calculate \(P(A \text{ and } B)\):**
- For event \(A \text{ and } B\) (choosing a red card that is also an ace), the relevant aces are the Ace of Diamonds and the Ace of Hearts. There are 2 red aces.
\[
P(A \text{ and } B) = \frac{2}{52} = \frac{1}{26}
\]
5. **Determine independence:**
- To check if events \(A\) and \(B\) are independent, we need to see if:
\[
P(A \text{ and } B) = P(A) \times P(B)
\]
- Calculate \(P(A) \times P(B)\):
\[
P(A) \times P(B) = \frac{1}{2} \times \frac{1}{13} = \frac{1}{26}
\]
- Since \(P(A \text{ and } B) = P(A) \times P(B)\), events \(A\) and \(B\) are independent.
Putting it all together:
1. \(P(A \text{ and } B) = \frac{1}{26}\)
2. \(P(A) = \frac{1}{2}\)
3. \(P(B) = \frac{1}{13}\)
4. Events \(A\) and \(B\) are independent (enter 2).
Final answers:
- \(P(A \text{ and } B) = \frac{1}{26}\)
- \(P(A) = \frac{1}{2}\)
- \(P(B) = \frac{1}{13}\)
- Events are independent (2).