Question
Right Rectangular Prisms & Pyramids Unit Test
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Question
A rectangular pyramid has a length of 7 cm and a width of 9 cm. Its volume is 231 cubic centimeters. Use the formula for the volume of a pyramid to calculate the height of this pyramid. Show all your work.(2 points)
Math Short Answer Rubric (2 points)
Points Awarded Criteria
2
The answer is correct. The student made no errors while solving.
The answer shows that the student used problem-solving skills and reasoning.
All work is shown or explained.
1
The answer is partially correct. The student made errors while solving.
The answer shows little problem-solving skills or reasoning.
Some work is shown or explained.
0 The question is not answered.
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15 of 1515 of 15 Items
Question
A rectangular pyramid has a length of 7 cm and a width of 9 cm. Its volume is 231 cubic centimeters. Use the formula for the volume of a pyramid to calculate the height of this pyramid. Show all your work.(2 points)
Math Short Answer Rubric (2 points)
Points Awarded Criteria
2
The answer is correct. The student made no errors while solving.
The answer shows that the student used problem-solving skills and reasoning.
All work is shown or explained.
1
The answer is partially correct. The student made errors while solving.
The answer shows little problem-solving skills or reasoning.
Some work is shown or explained.
0 The question is not answered.
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Answers
GPT-4o mini
To find the height of the rectangular pyramid, we can use the formula for the volume of a pyramid:
\[
V = \frac{1}{3} \times l \times w \times h
\]
Where:
- \( V \) is the volume of the pyramid,
- \( l \) is the length,
- \( w \) is the width,
- \( h \) is the height.
Given:
- Volume \( V = 231 \) cubic centimeters,
- Length \( l = 7 \) cm,
- Width \( w = 9 \) cm.
We can substitute the known values into the formula:
\[
231 = \frac{1}{3} \times 7 \times 9 \times h
\]
First, we calculate \( \frac{1}{3} \times 7 \times 9 \):
\[
7 \times 9 = 63
\]
\[
\frac{1}{3} \times 63 = 21
\]
Now our equation looks like this:
\[
231 = 21 \times h
\]
Next, we solve for \( h \) by dividing both sides of the equation by 21:
\[
h = \frac{231}{21}
\]
Calculating the right side:
\[
h = 11
\]
Thus, the height of the pyramid is:
\[
\boxed{11 \text{ cm}}
\]
\[
V = \frac{1}{3} \times l \times w \times h
\]
Where:
- \( V \) is the volume of the pyramid,
- \( l \) is the length,
- \( w \) is the width,
- \( h \) is the height.
Given:
- Volume \( V = 231 \) cubic centimeters,
- Length \( l = 7 \) cm,
- Width \( w = 9 \) cm.
We can substitute the known values into the formula:
\[
231 = \frac{1}{3} \times 7 \times 9 \times h
\]
First, we calculate \( \frac{1}{3} \times 7 \times 9 \):
\[
7 \times 9 = 63
\]
\[
\frac{1}{3} \times 63 = 21
\]
Now our equation looks like this:
\[
231 = 21 \times h
\]
Next, we solve for \( h \) by dividing both sides of the equation by 21:
\[
h = \frac{231}{21}
\]
Calculating the right side:
\[
h = 11
\]
Thus, the height of the pyramid is:
\[
\boxed{11 \text{ cm}}
\]