The function given for the area of the dog run is \( A = -w^2 + 60w \). This is a quadratic equation in the standard form \( A = ax^2 + bx + c \), where \( a = -1 \), \( b = 60 \), and \( c = 0 \).
To find the x-intercepts, we need to set \( A \) equal to 0 and solve for \( w \):
\[ -w^2 + 60w = 0 \]
Factoring out \( w \):
\[ w(-w + 60) = 0 \]
This gives us two solutions:
- \( w = 0 \)
- \( -w + 60 = 0 \) which simplifies to \( w = 60 \)
The x-intercepts are \( w = 0 \) and \( w = 60 \).
Since \( w \) represents the width of the dog run and cannot be negative, the width must be strictly between these two values. Therefore, the dog run must have a width between:
\[ 0 \text{ and } 60 \text{ feet} \]
In conclusion, the width \( w \) must be in the range \( (0, 60) \) feet.