Question
Re-express 2 √-45 as a complex number in the form a+bi.
Answers
Answered by
GPT-4o mini
To re-express \(2 \sqrt{-45}\) as a complex number in the form \(a + bi\), we first simplify the expression.
1. Start with the square root of \(-45\):
\[
\sqrt{-45} = \sqrt{45} \cdot \sqrt{-1}
\]
Here, \(\sqrt{-1}\) is represented as \(i\) (the imaginary unit).
2. Next, calculate \(\sqrt{45}\):
\[
\sqrt{45} = \sqrt{9 \cdot 5} = \sqrt{9} \cdot \sqrt{5} = 3\sqrt{5}
\]
3. Now substitute back into the expression:
\[
\sqrt{-45} = 3\sqrt{5} \cdot i
\]
4. Multiply by 2 to get \(2 \sqrt{-45}\):
\[
2 \sqrt{-45} = 2 \cdot 3\sqrt{5} \cdot i = 6\sqrt{5} \cdot i
\]
5. Finally, express it in the form \(a + bi\):
\[
2 \sqrt{-45} = 0 + 6\sqrt{5} i
\]
Thus, the complex number in the form \(a + bi\) is:
\[
\boxed{0 + 6\sqrt{5} i}
\]
1. Start with the square root of \(-45\):
\[
\sqrt{-45} = \sqrt{45} \cdot \sqrt{-1}
\]
Here, \(\sqrt{-1}\) is represented as \(i\) (the imaginary unit).
2. Next, calculate \(\sqrt{45}\):
\[
\sqrt{45} = \sqrt{9 \cdot 5} = \sqrt{9} \cdot \sqrt{5} = 3\sqrt{5}
\]
3. Now substitute back into the expression:
\[
\sqrt{-45} = 3\sqrt{5} \cdot i
\]
4. Multiply by 2 to get \(2 \sqrt{-45}\):
\[
2 \sqrt{-45} = 2 \cdot 3\sqrt{5} \cdot i = 6\sqrt{5} \cdot i
\]
5. Finally, express it in the form \(a + bi\):
\[
2 \sqrt{-45} = 0 + 6\sqrt{5} i
\]
Thus, the complex number in the form \(a + bi\) is:
\[
\boxed{0 + 6\sqrt{5} i}
\]