Asked by mav welborn
17mm, 15mm, and b
What is the length of the missing leg? If necessary, round to the nearest tenth.
b=___ millimeters
What is the length of the missing leg? If necessary, round to the nearest tenth.
b=___ millimeters
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the length of the missing leg \( b \), we need more context about the problem. It seems like you may be referring to a right triangle, where 17 mm and 15 mm could be the lengths of the two legs, and \( b \) might be the hypotenuse or the length of the missing leg.
1. **If \( b \) is the hypotenuse:**
We can use the Pythagorean theorem:
\[
a^2 + b^2 = c^2
\]
Here, \( a = 15 \) mm and \( c = 17 \) mm. We can find \( b \) as follows:
\[
15^2 + b^2 = 17^2
\]
\[
225 + b^2 = 289
\]
\[
b^2 = 289 - 225
\]
\[
b^2 = 64
\]
\[
b = \sqrt{64} = 8 \text{ mm}
\]
2. **If \( b \) is one of the legs:**
Assuming \( b \) is the length of the missing leg and 17 mm is the hypotenuse:
\[
15^2 + b^2 = 17^2
\]
This set-up would be the same calculation as above, leading to:
\[
b = 8 \text{ mm}
\]
In both cases, if the problem is set up as a right triangle, the length of the missing leg \( b \) is \( 8 \) mm.
Please confirm if this is the case, or provide additional context if necessary!
1. **If \( b \) is the hypotenuse:**
We can use the Pythagorean theorem:
\[
a^2 + b^2 = c^2
\]
Here, \( a = 15 \) mm and \( c = 17 \) mm. We can find \( b \) as follows:
\[
15^2 + b^2 = 17^2
\]
\[
225 + b^2 = 289
\]
\[
b^2 = 289 - 225
\]
\[
b^2 = 64
\]
\[
b = \sqrt{64} = 8 \text{ mm}
\]
2. **If \( b \) is one of the legs:**
Assuming \( b \) is the length of the missing leg and 17 mm is the hypotenuse:
\[
15^2 + b^2 = 17^2
\]
This set-up would be the same calculation as above, leading to:
\[
b = 8 \text{ mm}
\]
In both cases, if the problem is set up as a right triangle, the length of the missing leg \( b \) is \( 8 \) mm.
Please confirm if this is the case, or provide additional context if necessary!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.