Asked by Marie
Cross product of vector:
If axb(cross product)=(2,0,1) and bxc= -4,0,-4
solve magnitude of axb times magnitude of b x c
|a x b| x|bxc|
If axb(cross product)=(2,0,1) and bxc= -4,0,-4
solve magnitude of axb times magnitude of b x c
|a x b| x|bxc|
Answers
Answered by
Reiny
|(2,0,1)| = √(4+0+1) = √5
|(-4,0,-4)| = √(16+0+16) = √32
so their product is √5√32 = √60 = 2√15
|(-4,0,-4)| = √(16+0+16) = √32
so their product is √5√32 = √60 = 2√15
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