Asked by M
A 25-foot ladder is placed against a vertical wall of a building. The base of the ladder is 7 feet from the base of the wall. If the top of the ladder slips 4 feet, how many feet will the base of the ladder slide?
Answers
Answered by
Ms. Sue
a^2 + b^2 = c^2
a^2 + 7^2 = 25^2
a^2 + 49 = 625
a^2 = 625 - 49
a^2 = 576
a = 24
24 - 4 = 20
20^2 + b^2 = 25^2
400 + b^2 = 625
b^2 = 225
b = 15
15 - 7 = 8
a^2 + 7^2 = 25^2
a^2 + 49 = 625
a^2 = 625 - 49
a^2 = 576
a = 24
24 - 4 = 20
20^2 + b^2 = 25^2
400 + b^2 = 625
b^2 = 225
b = 15
15 - 7 = 8
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.