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Question

A 25-foot ladder is placed against a vertical wall of a building. The base of the ladder is 7 feet from the base of the wall. If the top of the ladder slips 4 feet, how many feet will the base of the ladder slide?
15 years ago

Answers

Ms. Sue
a^2 + b^2 = c^2

a^2 + 7^2 = 25^2
a^2 + 49 = 625
a^2 = 625 - 49
a^2 = 576
a = 24

24 - 4 = 20

20^2 + b^2 = 25^2
400 + b^2 = 625
b^2 = 225
b = 15

15 - 7 = 8

15 years ago

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