Asked by Anonymous
part 1
When 0.633 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 103C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
The molar heat of reaction, H rxn, for the reaction of
Ca(s) + 2H+(aq) Ca2+(aq) + H2(g)
is kJ/mol.
part 2
When 0.911 g of CaO is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 374C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
Hrxn, for the reaction of
CaO(s) + 2H+(aq) Ca2+(aq) + H2O(l)
is kJ/mol.
part 3
Based on the results of problems 8 and 9 if the heat of formation of water is -286 kJ/mol,
The H ffor CaO(s) is
When 0.633 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 103C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
The molar heat of reaction, H rxn, for the reaction of
Ca(s) + 2H+(aq) Ca2+(aq) + H2(g)
is kJ/mol.
part 2
When 0.911 g of CaO is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 374C is observed.
Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC.
(Note: Pay attention to significant figures. Do not round until the final answer.)
Hrxn, for the reaction of
CaO(s) + 2H+(aq) Ca2+(aq) + H2O(l)
is kJ/mol.
part 3
Based on the results of problems 8 and 9 if the heat of formation of water is -286 kJ/mol,
The H ffor CaO(s) is
Answers
Answered by
*#_%!2
how do you do part 3?
i tried solving it multiple times...
i tried solving it multiple times...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.