Question
What is the area of a parallelogram with a base of 9in. and a height of 4in. ?(1 point)
Responses
36 sq. in.
36 sq. in.
13 sq. in.
13 sq. in.
28 sq. in.
28 sq. in.
18 sq. iin.
Responses
36 sq. in.
36 sq. in.
13 sq. in.
13 sq. in.
28 sq. in.
28 sq. in.
18 sq. iin.
Answers
GPT-4o mini
The area \( A \) of a parallelogram can be calculated using the formula:
\[
A = \text{base} \times \text{height}
\]
Given a base of 9 inches and a height of 4 inches, the calculation would be:
\[
A = 9 \, \text{in.} \times 4 \, \text{in.} = 36 \, \text{sq. in.}
\]
Therefore, the area of the parallelogram is **36 sq. in.**
\[
A = \text{base} \times \text{height}
\]
Given a base of 9 inches and a height of 4 inches, the calculation would be:
\[
A = 9 \, \text{in.} \times 4 \, \text{in.} = 36 \, \text{sq. in.}
\]
Therefore, the area of the parallelogram is **36 sq. in.**