Question
What is the sum of the following expression?
2√108+√48+5√27
(1 point)
Responses
8 square root of 183
13 square root of 3
31 square root of 183
31 square root of 3
2√108+√48+5√27
(1 point)
Responses
8 square root of 183
13 square root of 3
31 square root of 183
31 square root of 3
Answers
GPT-4o mini
To simplify the expression \( 2\sqrt{108}+\sqrt{48}+5\sqrt{27} \), we first simplify each term:
1. **Simplifying \( \sqrt{108} \)**:
\[
\sqrt{108} = \sqrt{36 \times 3} = \sqrt{36} \cdot \sqrt{3} = 6\sqrt{3}
\]
Therefore,
\[
2\sqrt{108} = 2 \cdot 6\sqrt{3} = 12\sqrt{3}
\]
2. **Simplifying \( \sqrt{48} \)**:
\[
\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3}
\]
3. **Simplifying \( 5\sqrt{27} \)**:
\[
\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}
\]
Therefore,
\[
5\sqrt{27} = 5 \cdot 3\sqrt{3} = 15\sqrt{3}
\]
Now, we combine all the simplified terms:
\[
12\sqrt{3} + 4\sqrt{3} + 15\sqrt{3} = (12 + 4 + 15)\sqrt{3} = 31\sqrt{3}
\]
Thus, the sum of the expression is \( \boxed{31 \sqrt{3}} \).
1. **Simplifying \( \sqrt{108} \)**:
\[
\sqrt{108} = \sqrt{36 \times 3} = \sqrt{36} \cdot \sqrt{3} = 6\sqrt{3}
\]
Therefore,
\[
2\sqrt{108} = 2 \cdot 6\sqrt{3} = 12\sqrt{3}
\]
2. **Simplifying \( \sqrt{48} \)**:
\[
\sqrt{48} = \sqrt{16 \times 3} = \sqrt{16} \cdot \sqrt{3} = 4\sqrt{3}
\]
3. **Simplifying \( 5\sqrt{27} \)**:
\[
\sqrt{27} = \sqrt{9 \times 3} = \sqrt{9} \cdot \sqrt{3} = 3\sqrt{3}
\]
Therefore,
\[
5\sqrt{27} = 5 \cdot 3\sqrt{3} = 15\sqrt{3}
\]
Now, we combine all the simplified terms:
\[
12\sqrt{3} + 4\sqrt{3} + 15\sqrt{3} = (12 + 4 + 15)\sqrt{3} = 31\sqrt{3}
\]
Thus, the sum of the expression is \( \boxed{31 \sqrt{3}} \).