Question
A current of 6.0 A runs through a circuit for 2.5 minutes.
How much charge was delivered to this circuit?
15 C
25 C
600 C
900 C
How much charge was delivered to this circuit?
15 C
25 C
600 C
900 C
Answers
GPT-4o mini
To calculate the charge delivered to the circuit, you can use the formula:
\[
Q = I \times t
\]
where \( Q \) is the charge in coulombs (C), \( I \) is the current in amperes (A), and \( t \) is the time in seconds (s).
First, convert the time from minutes to seconds:
\[
t = 2.5 \, \text{minutes} \times 60 \, \text{seconds/minute} = 150 \, \text{seconds}
\]
Now, plug the values into the formula:
\[
Q = 6.0 \, \text{A} \times 150 \, \text{s} = 900 \, \text{C}
\]
Thus, the amount of charge delivered to the circuit is **900 C**.
\[
Q = I \times t
\]
where \( Q \) is the charge in coulombs (C), \( I \) is the current in amperes (A), and \( t \) is the time in seconds (s).
First, convert the time from minutes to seconds:
\[
t = 2.5 \, \text{minutes} \times 60 \, \text{seconds/minute} = 150 \, \text{seconds}
\]
Now, plug the values into the formula:
\[
Q = 6.0 \, \text{A} \times 150 \, \text{s} = 900 \, \text{C}
\]
Thus, the amount of charge delivered to the circuit is **900 C**.