Question
In a species of bird, there is a dominant allele for long beaks (B) and a recessive allele for short beaks (b).
If a homozygous dominant, long-beaked bird is crossed with a homozygous recessive, short-beaked bird, what percent of the offspring would have short beaks?
0%
25%
50%
100%
If a homozygous dominant, long-beaked bird is crossed with a homozygous recessive, short-beaked bird, what percent of the offspring would have short beaks?
0%
25%
50%
100%
Answers
GPT-4o mini
In this scenario, we have:
- Homozygous dominant long-beaked bird: BB
- Homozygous recessive short-beaked bird: bb
When you cross these two birds (BB × bb), all offspring will inherit one allele from each parent.
The possible combinations for the offspring will be:
- From the BB parent, all offspring will inherit a B allele.
- From the bb parent, all offspring will inherit a b allele.
Therefore, all offspring will have the genotype Bb.
Since Bb represents a long-beaked phenotype (due to the dominance of the B allele), none of the offspring will have short beaks (bb).
Thus, the percent of the offspring that would have short beaks is **0%**.
- Homozygous dominant long-beaked bird: BB
- Homozygous recessive short-beaked bird: bb
When you cross these two birds (BB × bb), all offspring will inherit one allele from each parent.
The possible combinations for the offspring will be:
- From the BB parent, all offspring will inherit a B allele.
- From the bb parent, all offspring will inherit a b allele.
Therefore, all offspring will have the genotype Bb.
Since Bb represents a long-beaked phenotype (due to the dominance of the B allele), none of the offspring will have short beaks (bb).
Thus, the percent of the offspring that would have short beaks is **0%**.