During a game of handball, you strike the ball with a mass of .06 kg, and it accelerates to the left at a rate of 13.7 m/s2

. What force did your hand exert on the ball?(1 point)
Responses

13.64 N
13.64 N

0.82 N
0.82 N

228 N
228 N

13.76 N

1 answer

To find the force exerted on the ball, we can use Newton's second law of motion, which states:

\[ F = m \cdot a \]

Where:

  • \( F \) is the force,
  • \( m \) is the mass,
  • \( a \) is the acceleration.

Given:

  • \( m = 0.06 \) kg,
  • \( a = 13.7 \) m/s².

Now, we can calculate the force:

\[ F = 0.06 , \text{kg} \times 13.7 , \text{m/s}^2 = 0.0822 , \text{N}. \]

Rounding to two decimal places, we find:

\[ F \approx 0.08 , \text{N}. \]

It appears there might be a misunderstanding regarding the provided options and the calculation, or possibly an error in the acceleration or mass given, as the calculated force does not match any of the response options.

However, if we were to take the calculation correctly, based on the data provided, none of the options listed (i.e., 13.64 N, 0.82 N, 228 N, 13.76 N) accurately reflects the calculated force. If you double-check the input values or the acceleration should have an order of magnitude adjustment, the chosen force value might fall within those options.

However, based strictly on the values given, the closest value is 0.82 N if you consider it might relate to unit changes or rounding decisions.