Question
Slope of a graph with two dots (2,0) and (0,-2)
What is base also
What is base also
Answers
Answer
How about (3,-1) and (0,1)
Answered by
GPT-4o mini
To find the slope of a line given two points, you can use the slope formula:
\[
\text{slope} (m) = \frac{y_2 - y_1}{x_2 - x_1}
\]
Given the points (2, 0) and (0, -2), you can assign:
- \( (x_1, y_1) = (2, 0) \)
- \( (x_2, y_2) = (0, -2) \)
Now, plug in the values:
\[
m = \frac{-2 - 0}{0 - 2} = \frac{-2}{-2} = 1
\]
So, the slope of the line is \( m = 1 \).
In terms of the "base," if you're referring to the distance between the two points along the x-axis (the horizontal distance), you can calculate it as:
\[
\text{base} = |x_2 - x_1| = |0 - 2| = 2
\]
If you're referring to something else by "base," please provide more details. But the distance between the points on the x-axis is 2.
\[
\text{slope} (m) = \frac{y_2 - y_1}{x_2 - x_1}
\]
Given the points (2, 0) and (0, -2), you can assign:
- \( (x_1, y_1) = (2, 0) \)
- \( (x_2, y_2) = (0, -2) \)
Now, plug in the values:
\[
m = \frac{-2 - 0}{0 - 2} = \frac{-2}{-2} = 1
\]
So, the slope of the line is \( m = 1 \).
In terms of the "base," if you're referring to the distance between the two points along the x-axis (the horizontal distance), you can calculate it as:
\[
\text{base} = |x_2 - x_1| = |0 - 2| = 2
\]
If you're referring to something else by "base," please provide more details. But the distance between the points on the x-axis is 2.
Answered by
GPT-4o mini
To find the slope of the line given the points (3, -1) and (0, 1), we can use the slope formula:
\[
\text{slope} (m) = \frac{y_2 - y_1}{x_2 - x_1}
\]
Using the points:
- \( (x_1, y_1) = (3, -1) \)
- \( (x_2, y_2) = (0, 1) \)
Now, substitute these values into the formula:
\[
m = \frac{1 - (-1)}{0 - 3} = \frac{1 + 1}{0 - 3} = \frac{2}{-3} = -\frac{2}{3}
\]
So, the slope of the line is \( m = -\frac{2}{3} \).
To find the base (the horizontal distance between the two points), we calculate:
\[
\text{base} = |x_2 - x_1| = |0 - 3| = 3
\]
Thus, for the points (3, -1) and (0, 1):
- The slope is \( -\frac{2}{3} \).
- The base (horizontal distance) is \( 3 \).
\[
\text{slope} (m) = \frac{y_2 - y_1}{x_2 - x_1}
\]
Using the points:
- \( (x_1, y_1) = (3, -1) \)
- \( (x_2, y_2) = (0, 1) \)
Now, substitute these values into the formula:
\[
m = \frac{1 - (-1)}{0 - 3} = \frac{1 + 1}{0 - 3} = \frac{2}{-3} = -\frac{2}{3}
\]
So, the slope of the line is \( m = -\frac{2}{3} \).
To find the base (the horizontal distance between the two points), we calculate:
\[
\text{base} = |x_2 - x_1| = |0 - 3| = 3
\]
Thus, for the points (3, -1) and (0, 1):
- The slope is \( -\frac{2}{3} \).
- The base (horizontal distance) is \( 3 \).
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