To solve the quadratic equation \((x+6)^2/2 = 8\) using square roots, follow these steps:
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Multiply both sides by 2 to eliminate the fraction:
\[ (x + 6)^2 = 16 \]
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Take the square root of both sides:
\[ x + 6 = \pm 4 \]
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Solve for \(x\) in each case:
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For the positive case: \[ x + 6 = 4 \implies x = 4 - 6 = -2 \]
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For the negative case: \[ x + 6 = -4 \implies x = -4 - 6 = -10 \]
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Combine the solutions:
The solutions are \(x = -2\) and \(x = -10\).
Thus, the solution set is \({-2, -10}\).
The correct response is: \[ {-2, -10} \]