Question

Determine whether the values −1
and 73
are solutions to the quadratic equation 3x2−4x−4=3
.(1 point)
Responses

Only x=−1
is a solution.
Only x equals negative 1 is a solution.

Neither x=−1
nor x=73
is a solution.
Neither x equals negative 1 nor x equals Start Fraction 7 over 3 End Fraction is a solution.

Both x=−1
and x=73
are solutions.
Both x equals negative 1 and x equals Start Fraction 7 over 3 End Fraction are solutions.

Only x=73
is a solution.
Only x equals Start Fraction 7 over 3 End Fraction is a solution.

Answer 1

To determine whether the values \( x = -1 \) and \( x = 73 \) are solutions to the quadratic equation \( 3x^2 - 4x - 4 = 3 \), we first rewrite the equation:

\[
3x^2 - 4x - 4 - 3 = 0 \implies 3x^2 - 4x - 7 = 0
\]

Now we will test both values, \( x = -1 \) and \( x = 73 \), in the equation \( 3x^2 - 4x - 7 = 0 \).

**Testing \( x = -1 \):**

\[
3(-1)^2 - 4(-1) - 7 = 3(1) + 4 - 7 = 3 + 4 - 7 = 0
\]

So, \( x = -1 \) is indeed a solution.

---

**Testing \( x = 73 \):**

\[
3(73)^2 - 4(73) - 7 = 3(5329) - 292 - 7
\]

Calculating \( 3(5329) \):

\[
3 \times 5329 = 15987
\]

Now, substituting back into the equation:

\[
15987 - 292 - 7 = 15987 - 299 = 15688
\]

Since \( 15688 \neq 0 \), \( x = 73 \) is not a solution.

---

Thus, the final conclusion is:

**Only \( x = -1 \) is a solution.**