Question
A gardener uses a wheelbarrow as a lever to lift some dirt. The energy applied by the gardener is 2,000 joules. The efficiency of the work done is 95%. How much work is done on the dirt?(1 point) Responses 1,905 joules 1,905 joules 2,000 joules 2,000 joules 2,105 joules 2,105 joules 1,900 joules
Answers
GPT-4o mini
To find the work done on the dirt, we can use the formula for efficiency:
\[
\text{Efficiency} = \frac{\text{Work output}}{\text{Work input}} \times 100\%
\]
Given that the efficiency is 95% and the work input (energy applied by the gardener) is 2,000 joules, we can rearrange the formula to find the work output:
\[
\text{Work output} = \text{Efficiency} \times \text{Work input}
\]
Substituting in the values, we convert the efficiency percentage to a decimal:
\[
\text{Work output} = 0.95 \times 2000 \, \text{joules}
\]
Calculating the work output:
\[
\text{Work output} = 1900 \, \text{joules}
\]
So, the work done on the dirt is **1,900 joules**.
\[
\text{Efficiency} = \frac{\text{Work output}}{\text{Work input}} \times 100\%
\]
Given that the efficiency is 95% and the work input (energy applied by the gardener) is 2,000 joules, we can rearrange the formula to find the work output:
\[
\text{Work output} = \text{Efficiency} \times \text{Work input}
\]
Substituting in the values, we convert the efficiency percentage to a decimal:
\[
\text{Work output} = 0.95 \times 2000 \, \text{joules}
\]
Calculating the work output:
\[
\text{Work output} = 1900 \, \text{joules}
\]
So, the work done on the dirt is **1,900 joules**.