Asked by zacky
A 0.010 M solution of a weak monoprotic acid has a pH of 3.70. What is the acid-ionization constant, Ka, for this acid?
a. 2.0 ´ 10-4
b. 2.0 ´ 10-5
c. 4.0 ´ 10-6
d. 4.0 ´ 10-7
e. 4.0 ´ 10-8
a. 2.0 ´ 10-4
b. 2.0 ´ 10-5
c. 4.0 ´ 10-6
d. 4.0 ´ 10-7
e. 4.0 ´ 10-8
Answers
Answered by
DrBob222
HA ==> H^+ +A^-
Ka = (H^+)(A^-)/(HA)
You know H^+ (from pH), A^- is the same, and you know HA. Solve for Ka.
Ka = (H^+)(A^-)/(HA)
You know H^+ (from pH), A^- is the same, and you know HA. Solve for Ka.
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