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A rectangular pyramid has a length of 7 cm and a width of 9 cm. Its volume is 231 cubic centimeters. Use the formula for the vo...Asked by ghi
A rectangular pyramid has a length of 7 cm and a width of 9 cm. Its volume is 231 cubic centimeters. Use the formula for the volume of a pyramid to calculate the height of this pyramid. Show all your work.
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40 words limit
Answers
Answered by
ghi
Where did 231 and 693 come from?
Answered by
GPT-4o mini
The volume \( V \) of a pyramid is given by the formula:
\[
V = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]
For a rectangular pyramid:
\[
\text{Base Area} = \text{Length} \times \text{Width} = 7 \, \text{cm} \times 9 \, \text{cm} = 63 \, \text{cm}^2
\]
Substituting into the volume formula:
\[
231 = \frac{1}{3} \times 63 \times h
\]
Multiplying both sides by 3:
\[
693 = 63h
\]
Solving for \( h \):
\[
h = \frac{693}{63} = 11 \, \text{cm}
\]
Thus, the height of the pyramid is **11 cm**.
\[
V = \frac{1}{3} \times \text{Base Area} \times \text{Height}
\]
For a rectangular pyramid:
\[
\text{Base Area} = \text{Length} \times \text{Width} = 7 \, \text{cm} \times 9 \, \text{cm} = 63 \, \text{cm}^2
\]
Substituting into the volume formula:
\[
231 = \frac{1}{3} \times 63 \times h
\]
Multiplying both sides by 3:
\[
693 = 63h
\]
Solving for \( h \):
\[
h = \frac{693}{63} = 11 \, \text{cm}
\]
Thus, the height of the pyramid is **11 cm**.
Answered by
GPT-4o mini
Apologies for any confusion. Here’s a clearer breakdown:
1. **Given Information**:
- Length of the pyramid, \( l = 7 \, \text{cm} \)
- Width of the pyramid, \( w = 9 \, \text{cm} \)
- Volume of the pyramid, \( V = 231 \, \text{cm}^3 \)
2. **Base Area Calculation**:
\[
\text{Base Area} = l \times w = 7 \, \text{cm} \times 9 \, \text{cm} = 63 \, \text{cm}^2
\]
3. **Volume Formula**:
The volume \( V \) of a pyramid is calculated using:
\[
V = \frac{1}{3} \times \text{Base Area} \times h
\]
4. **Substituting in Values**:
\[
231 = \frac{1}{3} \times 63 \times h
\]
5. **Multiplying Both Sides by 3**:
This step eliminates the fraction:
\[
3 \times 231 = 63h \implies 693 = 63h
\]
6. **Solving for Height \( h \)**:
To find \( h \):
\[
h = \frac{693}{63} = 11 \, \text{cm}
\]
Thus, the height of the pyramid is \( **11 \, \text{cm}**.
1. **Given Information**:
- Length of the pyramid, \( l = 7 \, \text{cm} \)
- Width of the pyramid, \( w = 9 \, \text{cm} \)
- Volume of the pyramid, \( V = 231 \, \text{cm}^3 \)
2. **Base Area Calculation**:
\[
\text{Base Area} = l \times w = 7 \, \text{cm} \times 9 \, \text{cm} = 63 \, \text{cm}^2
\]
3. **Volume Formula**:
The volume \( V \) of a pyramid is calculated using:
\[
V = \frac{1}{3} \times \text{Base Area} \times h
\]
4. **Substituting in Values**:
\[
231 = \frac{1}{3} \times 63 \times h
\]
5. **Multiplying Both Sides by 3**:
This step eliminates the fraction:
\[
3 \times 231 = 63h \implies 693 = 63h
\]
6. **Solving for Height \( h \)**:
To find \( h \):
\[
h = \frac{693}{63} = 11 \, \text{cm}
\]
Thus, the height of the pyramid is \( **11 \, \text{cm}**.
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