Question

Which correctly shows the area formula for a trapezoid, A=12h(b1+b2)
, rearranged for the quantity of interest h?(1 point)
Responses

h=12A(b1+b2)
h equals Start Fraction 1 over 2 End Fraction upper A left parenthesis b subscript 1 baseline plus b subscript 2 baseline right parenthesis

b1=2Ah−b2
b subscript 1 baseline dequals Start Fraction 2 upper A over h End Fraction minus b subscript 2 baseline

h=2Ab1+b2
h equals Start Fraction 2 upper A over b subscript 1 baseline plus b subscript 2 baseline End Fraction

h=b1+b22A

Answer 1

To rearrange the area formula for a trapezoid \( A = \frac{1}{2} h (b_1 + b_2) \) for \( h \), you can follow these steps:

1. Start with the area formula:
\[
A = \frac{1}{2} h (b_1 + b_2)
\]
2. Multiply both sides by 2 to eliminate the fraction:
\[
2A = h (b_1 + b_2)
\]
3. Now, divide both sides by \( (b_1 + b_2) \):
\[
h = \frac{2A}{b_1 + b_2}
\]

Thus, the correct rearranged formula for \( h \) is:

\[
h = \frac{2A}{b_1 + b_2}
\]

So, the response that matches this rearranged formula is:

**h = 2A/(b1 + b2)**