Complete the square to determine the vertex and axis of symmetry of y=−x^2+8x+7.(4 points)

1 answer

To complete the square for the quadratic function \( y = -x^2 + 8x + 7 \), we'll follow these steps:

  1. Factor out the coefficient of \( x^2 \) from the first two terms. Since the coefficient is negative, we'll factor out \(-1\):

    \[ y = -1(x^2 - 8x) + 7 \]

  2. Complete the square for the expression inside the parentheses (\( x^2 - 8x \)). To complete the square, take half of the coefficient of \( x \) (which is \(-8\)), square it, and add and subtract that value inside the parentheses. Half of \(-8\) is \(-4\), and squared is \(16\).

    \[ y = -1(x^2 - 8x + 16 - 16) + 7 \]

    This allows us to rewrite the equation as:

    \[ y = -1((x - 4)^2 - 16) + 7 \]

  3. Distribute the \(-1\):

    \[ y = -1(x - 4)^2 + 16 + 7 \]

    Simplifying gives us:

    \[ y = -1(x - 4)^2 + 23 \]

  4. Identify the vertex and axis of symmetry: The vertex form of a parabola is given by \( y = a(x - h)^2 + k \), where \((h, k)\) is the vertex.

    In this case, the vertex is \((4, 23)\).

    The axis of symmetry is given by the line \( x = h \). Therefore, the axis of symmetry is \( x = 4 \).

Final results:

  • Vertex: \( (4, 23) \)
  • Axis of symmetry: \( x = 4 \)