Asked by Amrita
Calculate the [H3O+] when 1.65 grams of KOH are dissolved in 500.0 mL of solution
Answers
Answered by
DrBob222
moles KOH = grams/molar mass.
solve for moles.
(KOH) = moles/L
solve for (KOH) = ?? molar.
That will be the OH^-.
(H^+)(OH^-) = 1 x 10^-14
solve for (H^+).
solve for moles.
(KOH) = moles/L
solve for (KOH) = ?? molar.
That will be the OH^-.
(H^+)(OH^-) = 1 x 10^-14
solve for (H^+).
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