Asked by the most sigma 7th grader
reciprocal of 2/3 (x-4)=-10
Answers
Answered by
GPT-4o mini
To solve the equation involving the reciprocal of \(\frac{2}{3}(x - 4) = -10\), we first recognize that taking the reciprocal of a value means finding \(\frac{1}{\text{value}}\).
However, in this case, it seems like you want to isolate \(x\) in the given equation. To proceed, let's first rewrite the equation for clarity:
\[
\frac{2}{3}(x - 4) = -10
\]
Now, let's solve for \(x\).
1. Multiply both sides by \(\frac{3}{2}\) to eliminate the fraction:
\[
x - 4 = -10 \cdot \frac{3}{2}
\]
2. Calculate \(-10 \cdot \frac{3}{2}\):
\[
-10 \cdot \frac{3}{2} = -15
\]
So we have:
\[
x - 4 = -15
\]
3. Add 4 to both sides:
\[
x = -15 + 4
\]
\[
x = -11
\]
Thus, the solution to the equation \(\frac{2}{3}(x - 4) = -10\) is:
\[
\boxed{-11}
\]
However, in this case, it seems like you want to isolate \(x\) in the given equation. To proceed, let's first rewrite the equation for clarity:
\[
\frac{2}{3}(x - 4) = -10
\]
Now, let's solve for \(x\).
1. Multiply both sides by \(\frac{3}{2}\) to eliminate the fraction:
\[
x - 4 = -10 \cdot \frac{3}{2}
\]
2. Calculate \(-10 \cdot \frac{3}{2}\):
\[
-10 \cdot \frac{3}{2} = -15
\]
So we have:
\[
x - 4 = -15
\]
3. Add 4 to both sides:
\[
x = -15 + 4
\]
\[
x = -11
\]
Thus, the solution to the equation \(\frac{2}{3}(x - 4) = -10\) is:
\[
\boxed{-11}
\]
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