To find the volume of a pyramid, you can use the formula:
\[ V = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
where the Base Area is calculated as \(\text{length} \times \text{width}\).
Now, we can solve the questions one by one:
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Volume of the pyramid with a base of 10 cm x 7 cm and height of 11 cm:
- Base Area = \(10 , \text{cm} \times 7 , \text{cm} = 70 , \text{cm}^2\)
- Volume = \(\frac{1}{3} \times 70 , \text{cm}^2 \times 11 , \text{cm} = \frac{770}{3} , \text{cm}^3 \approx 256.67 , \text{cm}^3\)
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Volume of the pyramid with a base of 24 ft x 15 ft and height of 20 ft:
- Base Area = \(24 , \text{ft} \times 15 , \text{ft} = 360 , \text{ft}^2\)
- Volume = \(\frac{1}{3} \times 360 , \text{ft}^2 \times 20 , \text{ft} = \frac{7200}{3} , \text{ft}^3 = 2400 , \text{ft}^3\)
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Volume of a right rectangular pyramid with height 22.3 in, length 6.75 in, and width 10.25 in:
- Base Area = \(6.75 , \text{in} \times 10.25 , \text{in} = 69.1875 , \text{in}^2\)
- Volume = \(\frac{1}{3} \times 69.1875 , \text{in}^2 \times 22.3 , \text{in} = \frac{1546.760625}{3} , \text{in}^3 \approx 515.59 , \text{in}^3\)
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Volume of the Eiffel Tower as a square pyramid with base 125 m x 125 m and height 324 m:
- Base Area = \(125 , \text{m} \times 125 , \text{m} = 15625 , \text{m}^2\)
- Volume = \(\frac{1}{3} \times 15625 , \text{m}^2 \times 324 , \text{m} = \frac{5062500}{3} , \text{m}^3 \approx 1687500 , \text{m}^3\)
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Volume of Cecilia's model pyramid with height 20 in, length 8 in, and width 12 in:
- Base Area = \(8 , \text{in} \times 12 , \text{in} = 96 , \text{in}^2\)
- Volume = \(\frac{1}{3} \times 96 , \text{in}^2 \times 20 , \text{in} = \frac{1920}{3} , \text{in}^3 = 640 , \text{in}^3\)
Summary of Volumes:
- Approximately 256.67 cm³
- 2400 ft³
- Approximately 515.59 in³
- Approximately 1687500 m³
- 640 in³
11 answers