Use the graph of velocity vs. time for an object to answer the question.





A line graph that displays the change in velocity over time and is broken up into 3 segments. At zero seconds, the velocity is zero meters per second. At 60 seconds, the velocity is 8 meters per second. The time difference between zero and 60 seconds represents the first segment. At 150 seconds, the velocity is 14 meters per second. The time difference between 60 and 150 seconds represents the second segment. At 240 seconds, the velocity is 29 meters per second. The time difference between 150 and 240 represents the third segment.
Which statement fairly compares segment 2 and segment 3?

(1 point)
Responses

Segments 2 and 3 have different periods of time, but the force acting in each segment is the same during each period of time.
Segments 2 and 3 have different periods of time, but the force acting in each segment is the same during each period of time.

Segments 2 and 3 have equal periods of time and the force acting in each segment is the same during each period of time.
Segments 2 and 3 have equal periods of time and the force acting in each segment is the same during each period of time.

Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3.
Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3.

Segments 2 and 3 have different periods of time and the force during segment 2 is different than the force during segment 3.

1 answer

To analyze the motion and compare segments 2 and 3, we need to look at the change in velocity and the time intervals for each segment.

  • Segment 2 (from 60 seconds to 150 seconds):

    • Initial velocity at 60 seconds: 8 m/s
    • Final velocity at 150 seconds: 14 m/s
    • Change in velocity: 14 m/s - 8 m/s = 6 m/s
    • Time duration: 150 seconds - 60 seconds = 90 seconds
  • Segment 3 (from 150 seconds to 240 seconds):

    • Initial velocity at 150 seconds: 14 m/s
    • Final velocity at 240 seconds: 29 m/s
    • Change in velocity: 29 m/s - 14 m/s = 15 m/s
    • Time duration: 240 seconds - 150 seconds = 90 seconds

From this, we can see that both segments 2 and 3 have a time duration of 90 seconds. However, the change in velocity (and thus the acceleration) is different between the two segments:

  • Segment 2 has an acceleration of \( \frac{6 , \text{m/s}}{90 , \text{s}} = 0.067 , \text{m/s}^2 \)
  • Segment 3 has an acceleration of \( \frac{15 , \text{m/s}}{90 , \text{s}} = 0.167 , \text{m/s}^2 \)

Since the change in velocity (and thus the net force, following Newton's second law) is different, the correct statement comparing segments 2 and 3 is:

"Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3."

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