Question
If 4 pounds of grass seed covers 92 square feet, how many pounds are needed to cover 290 square feet?
202 pounds
71 pounds
43 pounds
13 pounds
Answers
GPT-4o mini
To find out how many pounds of grass seed are needed to cover 290 square feet, we can start by determining the coverage per pound of grass seed from the initial information provided.
If 4 pounds of grass seed covers 92 square feet, then:
1. Find the coverage per pound:
\[
\text{Coverage per pound} = \frac{92 \text{ square feet}}{4 \text{ pounds}} = 23 \text{ square feet per pound}
\]
2. Now, we need to find how many pounds are needed to cover 290 square feet:
\[
\text{Pounds needed} = \frac{290 \text{ square feet}}{23 \text{ square feet per pound}} \approx 12.61 \text{ pounds}
\]
Since you cannot buy a fraction of a pound, round up to the nearest whole pound, which would be 13 pounds.
Thus, the answer is **13 pounds**.
If 4 pounds of grass seed covers 92 square feet, then:
1. Find the coverage per pound:
\[
\text{Coverage per pound} = \frac{92 \text{ square feet}}{4 \text{ pounds}} = 23 \text{ square feet per pound}
\]
2. Now, we need to find how many pounds are needed to cover 290 square feet:
\[
\text{Pounds needed} = \frac{290 \text{ square feet}}{23 \text{ square feet per pound}} \approx 12.61 \text{ pounds}
\]
Since you cannot buy a fraction of a pound, round up to the nearest whole pound, which would be 13 pounds.
Thus, the answer is **13 pounds**.