Question

Q
Xx
What percentage of the female offspring will be a carrier for this recessive disease?
Y
YXY
50%
25%
0%
100%

Answer 1

To determine the percentage of female offspring that will be carriers for a recessive disease in a genetic cross, we need to know the genotypes of the parents involved.

From your notation, it seems like you might be using a standard notation for sex-linked traits. If we interpret 'X' as the normal allele and 'x' as the recessive allele, here's a typical example:

Let’s assume:
- The mother is Xx (carrier for the recessive disease).
- The father is XY (normal, not affected).

When they have offspring, we can set up a Punnett square:

- Female offspring can be:
- XX (not a carrier)
- Xx (carrier)

- Male offspring can be:
- XY (normal)
- Xy (affected)

The combinations for female offspring from Xx (mother) and XY (father) are:
- X from mother and X from father → XX (not a carrier)
- x from mother and X from father → Xx (carrier)

So among the female offspring:
- 50% will be XX (not carriers)
- 50% will be Xx (carriers)

Therefore, **50% of the female offspring will be carriers for this recessive disease**.

So, the answer is **50%**.