To find the first five terms of the sequence defined by the recursive formula \( a_n = 2(a_{n-1}) + 5 \) with the initial value \( a_1 = -3 \), we will calculate each term step-by-step.
-
First Term: \( a_1 = -3 \)
-
Second Term: \[ a_2 = 2(a_1) + 5 = 2(-3) + 5 = -6 + 5 = -1 \]
-
Third Term: \[ a_3 = 2(a_2) + 5 = 2(-1) + 5 = -2 + 5 = 3 \]
-
Fourth Term: \[ a_4 = 2(a_3) + 5 = 2(3) + 5 = 6 + 5 = 11 \]
-
Fifth Term: \[ a_5 = 2(a_4) + 5 = 2(11) + 5 = 22 + 5 = 27 \]
Putting it all together, the first five terms of the sequence are: \[ -3, -1, 3, 11, 27 \]
Therefore, the correct response is: negative 3, negative 1, 3, 11, 27.