To determine if the graph accurately represents the piecewise function, let's analyze the function and its domain segments.
The piecewise function provided is:
- \( f(x) = 0.5 \) for \( 1 \leq x \leq 3 \)
- \( f(x) = 1.0 \) for \( 3 < x \leq 6 \)
- \( f(x) = 0.5x \) for \( x > 6 \)
Now, let's examine the characteristics of the graph based on these segments:
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For the segment \( 1 \leq x \leq 3 \) where \( f(x) = 0.5 \), the value is a constant. At \( x = 1 \) and \( x = 3 \), we include these points with closed circles.
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For \( 3 < x \leq 6 \) where \( f(x) = 1.0 \), at \( x = 3 \), there should be an open circle (since 3 is not included in this segment), and a closed circle at \( x = 6 \) since it’s included.
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For \( x > 6 \), \( f(x) = 0.5x \), this function increases as \( x \) increases, starting from the point \( (6, 3) \) (when plugging \( x = 6 \) into \( f(x) \)) which would have a closed circle.
Based on this analysis, the correct response would be:
No. There should be an open circle at the first point of the second part of the function (at \( x = 3 \)).
This choice correctly acknowledges that at \( x = 3 \), \( f(x) \) switches from one defined segment to another, and this point should be represented with an open circle in the graph.