Question

The built-in Python function slice allows the programmer to select portions of the input that they want to slice out. It has two possible syntaxes, slice(stop) or slice(start, stop, step). In the single parameter version, start and step default to none. The following code will print “Str”.

String = 'String slicing'
s1 = slice(3)
print(String[s1])

Which of the following will result in the string “ti”?

(1 point)
Responses

s1 = slice(1, 5, 2)
s1 = slice(1, 5, 2)

s1 = slice(2,6)
s1 = slice(2,6)

s1 = slice(2, 6, 2)
s1 = slice(2, 6, 2)

s1 = slice(1, 5)

Answer 1

To determine which option will result in the string "ti", let's analyze each slice operation based on the string `"String slicing"`.

Here’s how slicing works:
- The syntax is `slice(start, stop, step)`.
- The slice will start at the `start` index (inclusive), go up to the `stop` index (exclusive), and take every `step` element in that range.

The length of the string `"String slicing"` is 14. The indices are as follows:

```
S t r i n g s l i c i n g
0 1 2 3 4 5 6 7 8 9 10 11 12 13
```

For the string to slice out "ti":
- "t" is at index 1
- "i" is at index 3

To get "ti", we need to select the characters at indices 1 and 3, which means:
1. We start at index 1 (inclusive).
2. We go up to index 4 (exclusive, so index 3 is included).
3. We need to step by 2 to get the first character at index 1 and the next character at index 3.

Now let’s evaluate the provided options:

1. **`s1 = slice(1, 5, 2)`**
- This will yield characters at indices 1, 3 (inclusive): "ti".
- This option produces "ti".

2. **`s1 = slice(2, 6)`**
- This will yield characters at indices 2, 3, 4, 5: "rin" (does not produce "ti").

3. **`s1 = slice(2, 6, 2)`**
- This will yield characters at indices 2, 4: "ng" (does not produce "ti").

4. **`s1 = slice(1, 5)`**
- This will yield characters at indices 1, 2, 3, 4: "trin" (does not produce "ti").

Therefore, the option that results in the string "ti" is:

**`s1 = slice(1, 5, 2)`**.