To find the vertex of the quadratic function given by the equation \( h = -6t^2 - 24t + 20 \), we can use the vertex formula for a parabola represented as \( h(t) = at^2 + bt + c \). The \( t \)-coordinate of the vertex can be found using the formula:
\[ t = -\frac{b}{2a} \]
In this case:
- \( a = -6 \)
- \( b = -24 \)
- \( c = 20 \)
Now, we can calculate the \( t \)-coordinate of the vertex:
\[ t = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
Next, we can find the \( h \)-coordinate of the vertex by substituting \( t = -2 \) back into the original function:
\[ h = -6(-2)^2 - 24(-2) + 20 \] \[ h = -6(4) + 48 + 20 \] \[ h = -24 + 48 + 20 \] \[ h = 24 + 20 = 44 \]
Therefore, the vertex of the function is at the point \( (-2, 44) \).
So, the correct response is:
(−2, 44)