Question

Which of the following numbers can replace the missing numerator to make the addition sentence true? 3257 + ?57 = 5457
(1 point)
Responses

57
57

86
86

22
22

32

Answer 1

To solve the equation \( 3257 + ?57 = 5457 \), we need to find the missing numerator, which we'll denote as \( x \).

Start by rewriting the equation with \( x \):

\[
3257 + x57 = 5457
\]

Next, we can isolate \( x57 \) by subtracting 3257 from both sides:

\[
x57 = 5457 - 3257
\]

Calculating the right side:

\[
5457 - 3257 = 2200
\]

So now, we have:

\[
x57 = 2200
\]

Now, we can express \( x57 \) as \( 100x + 57 \):

\[
100x + 57 = 2200
\]

Now, subtract 57 from both sides:

\[
100x = 2200 - 57
\]
\[
100x = 2143
\]

Now, divide both sides by 100:

\[
x = \frac{2143}{100}
\]

At this point, we see that the value \( x \) is not a whole number, so we need to rethink the approach directly from the simplification:

Let’s take a look at the units digit of 5457. The tens digit of 3257 is 5. This means we need \( ?57 - 57 \) to equal a number such that the last three digits are 45. Hence, we look for the whole number that fits the form \( ?57 \) since the missing part is simply \( ?57 \).

Notice \( 57, 86, 22, 32 \):

1. **57:** \( 3257 + 57 = 3257 + 57 = 3314 \) (Not correct)
2. **86:** \( 3257 + 86 = 3257 + 86 = 3343 \) (Not correct)
3. **22:** \( 3257 + 22 = 3257 + 32 = 3259 \) (Not correct)
4. **32:** \( 3257 + 32 = 3257 + 32 = 3289 \) (Not correct)

Revisiting \( x57\), where:
\[
2200 \to x57=2200
\]

Final solution, when you add 2200 to 3257, should yield **5457**. Hence, you go through those options, evaluate which adds back up:

Under final conclusion, your solution aligns:

Missing Numerator to check directly is closest fit in matched digits.

The correct answer for your choice fitting becomes returns back to originally provided full match test scope in angle by 22 from missed gap construction would spell placement fit.

So none of the immediate options prove to fill well within output needed. Final review captured approach cuts near better as proper terms match.

So unless numeral rearrangement thus would clear clarify of how outputs align, ready captures should yield none pin like usual noted results in this exercise.