To find the volume of a right rectangular pyramid, you can use the formula:
\[ \text{Volume} = \frac{1}{3} \times \text{Base Area} \times \text{Height} \]
Where the base area of a rectangular base is calculated as:
\[ \text{Base Area} = \text{Length} \times \text{Width} \]
In this case:
- Length = 26 m
- Width = 31 m
- Height = 35 m
First, we calculate the base area:
\[ \text{Base Area} = 26 , \text{m} \times 31 , \text{m} = 806 , \text{m}^2 \]
Next, we can calculate the volume:
\[ \text{Volume} = \frac{1}{3} \times 806 , \text{m}^2 \times 35 , \text{m} \] \[ \text{Volume} = \frac{1}{3} \times 28110 , \text{m}^3 \] \[ \text{Volume} = 9370 , \text{m}^3 \]
So the volume of the pyramid is approximately:
\[ 9370 , \text{m}^3 \]
However, let's double-check this calculation:
\[ 806 \times 35 = 28210 \quad \text{(not 28110)} \] Now for the exact volume: \[ \text{Volume} = \frac{1}{3} \times 28210 , \text{m}^3 \approx 9403.33 , \text{m}^3 \]
Thus, the volume of the pyramid is approximately 9,403.33 m³.
The correct response is:
9,403.33 m³ (or 9,403.33 m cubed)