Question

An object originally at rest is uniformly accelerated to a speed of 8.0 meters per second in 2.0 seconds. What is the acceleration of the object?

\large acceleration=\frac{v_{final}-v_{initial}}{time}

a
<p>10. m/s²</p>
b
<p>0.25 m/s²</p>
c
<p>4.0 m/s²</p>
d
<p>16 m/s²</p>

Answer 1

To find the acceleration of the object, we will use the formula:

\[
\text{acceleration} = \frac{v_{\text{final}} - v_{\text{initial}}}{\text{time}}
\]

Given:
- \( v_{\text{final}} = 8.0 \, \text{m/s} \)
- \( v_{\text{initial}} = 0 \, \text{m/s} \) (since the object is originally at rest)
- \( \text{time} = 2.0 \, \text{s} \)

Now, substituting the values into the formula:

\[
\text{acceleration} = \frac{8.0 \, \text{m/s} - 0 \, \text{m/s}}{2.0 \, \text{s}} = \frac{8.0 \, \text{m/s}}{2.0 \, \text{s}} = 4.0 \, \text{m/s}^2
\]

Thus, the acceleration of the object is

\[
\boxed{4.0 \, \text{m/s}^2}
\]

So the correct answer is **c** \(4.0 \, \text{m/s}^2\).