To determine which point on the graph is a solution for the simultaneous inequalities \( y > 4x - 2 \) and \( y \geq -13x + 2 \), you need to analyze the inequalities based on their corresponding lines.
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Graph the lines:
- For \( y = 4x - 2 \):
- This line has a slope of 4 and a y-intercept of -2. The area above this line (where \( y > 4x - 2 \)) is the solution for the first inequality.
- For \( y = -13x + 2 \):
- This line has a slope of -13 and a y-intercept of 2. The area above or on this line (where \( y \geq -13x + 2 \)) is the solution for the second inequality.
- For \( y = 4x - 2 \):
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Identify the solution region:
- The solution region for the simultaneous inequalities is where the regions determined by both inequalities overlap.
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Check the points given on the graph to see which one lies in the overlapping region.
Since I don't have access to the image or graph you are referencing, please locate the points on the graph that fall within the above-mentioned regions.
Once you've identified a valid point:
- Enter the x-value followed by the y-value of that point.
If you provide the points or more specific details, I can help verify if they satisfy the inequalities.
1 answer