To find the volume of the gas tank, we need to determine its shape. If the gas tank is cylindrical, we will use the formula for the volume of a cylinder, which is:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the base,
- \( h \) is the height of the cylinder.
From the question, we are given the height \( h = 8 \) feet. The width of the tank is 6 feet, which indicates the diameter of the base. To find the radius, we divide the diameter by 2:
\[ r = \frac{6}{2} = 3 \text{ feet} \]
Now we can substitute the values into the volume formula:
\[ V = \pi r^2 h = 3.14 \times (3)^2 \times 8 \]
Calculating \( (3)^2 \):
\[ (3)^2 = 9 \]
Now substitute back into the volume formula:
\[ V = 3.14 \times 9 \times 8 \]
Calculating \( 9 \times 8 \):
\[ 9 \times 8 = 72 \]
So now we have:
\[ V = 3.14 \times 72 \]
Calculating \( 3.14 \times 72 \):
\[ V = 226.08 \]
Thus, the volume of the gas tank is:
\[ \boxed{226.08} \text{ cubic feet} \]
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