Question
Solve the following quadratic equation for all values of xx in simplest form.
4, left parenthesis, x, squared, minus, 7, right parenthesis, minus, 10, equals, minus, 13
4(x
2
−7)−10=
−13
4, left parenthesis, x, squared, minus, 7, right parenthesis, minus, 10, equals, minus, 13
4(x
2
−7)−10=
−13
Answers
GPT-4o mini
To solve the given quadratic equation:
\[ 4(x^2 - 7) - 10 = -13 \]
Let's simplify and solve step by step.
1. Distribute the 4 in the equation:
\[
4x^2 - 28 - 10 = -13
\]
2. Combine like terms:
\[
4x^2 - 38 = -13
\]
3. Add 38 to both sides to isolate the \(4x^2\):
\[
4x^2 = -13 + 38
\]
\[
4x^2 = 25
\]
4. Divide both sides by 4:
\[
x^2 = \frac{25}{4}
\]
5. Take the square root of both sides:
\[
x = \pm \sqrt{\frac{25}{4}}
\]
\[
x = \pm \frac{5}{2}
\]
Thus, the solutions for \(x\) are:
\[
x = \frac{5}{2} \quad \text{and} \quad x = -\frac{5}{2}
\]
In simplest form, the solutions are:
\[
x = \frac{5}{2}, \, -\frac{5}{2}
\]
\[ 4(x^2 - 7) - 10 = -13 \]
Let's simplify and solve step by step.
1. Distribute the 4 in the equation:
\[
4x^2 - 28 - 10 = -13
\]
2. Combine like terms:
\[
4x^2 - 38 = -13
\]
3. Add 38 to both sides to isolate the \(4x^2\):
\[
4x^2 = -13 + 38
\]
\[
4x^2 = 25
\]
4. Divide both sides by 4:
\[
x^2 = \frac{25}{4}
\]
5. Take the square root of both sides:
\[
x = \pm \sqrt{\frac{25}{4}}
\]
\[
x = \pm \frac{5}{2}
\]
Thus, the solutions for \(x\) are:
\[
x = \frac{5}{2} \quad \text{and} \quad x = -\frac{5}{2}
\]
In simplest form, the solutions are:
\[
x = \frac{5}{2}, \, -\frac{5}{2}
\]