Question
What is the equilibrium constant for the reaction:
HCOOH(aq)+ OH (aq) <--> HCOO(aq)+ H2O(l)
Ka= 1.7 * 10^-4
Kb for the conjugate base= 4.9 * 10^-11
Thank you!
HCOOH(aq)+ OH (aq) <--> HCOO(aq)+ H2O(l)
Ka= 1.7 * 10^-4
Kb for the conjugate base= 4.9 * 10^-11
Thank you!
Answers
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